Posted by **Amy** on Saturday, April 9, 2011 at 5:43pm.

Determine the perimeter and area of a rectangle that has a width of 6 inches and a length of 8 inches.

Using a ratio of 1:2, draw a similar rectangle that is double the width and length of the first shape. Determine the perimeter and area of this new rectangle.

Draw one more rectangle using a ratio of 1:3 (a rectangle that is triple the width and length of the original shape).

- Math -
**Ms. Sue**, Saturday, April 9, 2011 at 5:51pm
P = 2L + 2W

P = (2 * 8) + (2 * 6)

P = 16 + 12

P = 28

A = L * W

A = 6 * 8

A = 48 sq. inches

- Math -
**Anonymous**, Saturday, April 9, 2011 at 5:55pm
Thank you so much. I got that part but I don't understand using the ratio 1:2.

- Math -
**Bosnian**, Saturday, April 9, 2011 at 6:01pm
Perimeter of rectangle:

P=2w+2l

P=2(w+l)

Area of rectangle:

A=w*l

w=width

l=length

w=6in l=8in

P=2(w+l)

P=2*(6+8)=2*14=28in

A=w*l=6*8=48in^2

Ratio 1:2

w=2*6=12in l=2*8=16in

P=2(w+l)

P=2*(12+16)=2*28=56in

A=w*l=12*16=192in^2

Ratio 1:3

w=3*6=18in l=3*8=24in

P=2(w+l)

P=2*(18+24)=2*42=84in

A=w*l=18*24=432in^2

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