magnesium hydroxide + hydrobromic acid -->

is the formula for that

Mg(OH)2(s) + HBr(aq) ->H2O(l) +BrOH(s)

and are the physical states correct??

The formula for the reaction between magnesium hydroxide (Mg(OH)2) and hydrobromic acid (HBr) is correct:

Mg(OH)2(s) + HBr(aq) → H2O(l) + BrOH(s)

Regarding the physical states, the states you provided are correct. Mg(OH)2 is in solid form (s), HBr is in aqueous form (aq), H2O is in liquid form (l), and BrOH is in solid form (s).

The formula you provided for the reaction between magnesium hydroxide (Mg(OH)2) and hydrobromic acid (HBr) is correct. It shows that when magnesium hydroxide reacts with hydrobromic acid, water (H2O) and bromine hydroxide (BrOH) are produced.

Regarding the physical states of the substances, you have correctly identified that Mg(OH)2 is a solid (s) because it is written as (s) after the formula. HBr is written as (aq) which stands for "aqueous", indicating that hydrobromic acid is in the form of a solution in water. The arrow (->) indicates the direction of the reaction.

Water, H2O, is shown as (l) to represent its liquid state. BrOH is shown as (s), indicating that it is a solid.

So, in summary, the physical states you assigned are correct:
- Mg(OH)2 is a solid (s)
- HBr is an aqueous solution (aq)
- H2O is a liquid (l)
- BrOH is a solid (s)

Mg(OH)2(s) + HBr(aq) ==> 2H2O(l) + MgBr2(aq)

This is a typical acid/base reaction in which the products are a salt (MgBr2) + water(H2O).

This is not balanced