A catalytic reactor in an automobile is used to convert gas A to gas B where 3 mol of gas A diffuse to the catalyst for every 1 mol of B diffusing away at a distance (mm). the reaction balance is shown as follows: 3A-B
To answer the question, we need to find the number of moles of gas A and B involved in the reaction when given a distance in millimeters. We can use the concept of diffusion and stoichiometry to calculate the respective moles.
First, let's consider the stoichiometry of the reaction:
3A - B
This means that for every 3 moles of gas A, 1 mole of gas B is produced.
Next, let's determine the ratio of the diffusion distances for gas A and gas B. Let's assume that the distance for gas A is "x" millimeters and the distance for gas B is "y" millimeters.
Now, we can set up a proportion using the stoichiometric ratio and the diffusion distances:
(x mm)/(y mm) = (3 mol A)/(1 mol B)
Using this proportion, we can solve for either x or y, depending on the given information.
For example, if we are given the diffusion distance for gas A (x), we can calculate the diffusion distance for gas B (y) using the proportion:
y mm = (x mm) * (1 mol B)/(3 mol A)
Conversely, if we are given the diffusion distance for gas B (y), we can calculate the diffusion distance for gas A (x) using the proportion:
x mm = (y mm) * (3 mol A)/(1 mol B)
By manipulating the proportion and using the given information, we can determine the diffusion distances for gases A and B in millimeters.