Saturday

April 19, 2014

April 19, 2014

Posted by **patiance** on Friday, April 8, 2011 at 9:50pm.

N of AIDS cases in thousands can be approximated by N = -2x^2 + 76x + 430, Where x = 0 corresponds to the year 1993.

Year 1993 1995 1997 1999 2001 2003

Cases 422 565 677 762 844 930

(c) Rewrite the equation with the right side completely

factored.

Can someone explain to me how to do this please

- math -
**Bosnian**, Saturday, April 9, 2011 at 1:27amIn google type:

Rewrite the equation with the right side completely

When you see list of results click on:

AIDS Cases From 1993 to 2003 math help?

You will see solution.

- math -
**Candice**, Saturday, July 16, 2011 at 11:55am-2(x+5)(x-43)

**Related Questions**

algebra - From 1993 to 2003 the cumulative number N of AIDS cases in thousands ...

Algrebra - Please advise on the following: From 1993 to 2003 the cumulative ...

college algebra - 1984-1994 the equation the number of aids cases can be modeled...

college algebra - 1984-1994 the equation the number of aids cases can be modeled...

Algebra - The cumulative number of AIDS cases C in the United States from 1982...

MATH 208 - There were 18,017 AIDS deaths in 2003, or 34.5% of the 1995 AIDS ...

phoniex - there were 18,017 Aids deaths in 2003, or 34.5 percent of the 1995 ...

trig - N 5 22x2 1 76x 1 430 Use the equation to find N for each year in the ...

Math - The bar graph shows the cumulative number of death form AIDS in the US, ...

COM/220 - Please post your response to the following: o Identify the thesis ...