Posted by Anonymous on .
Find the perimeter of a regular hexagon that has an area of 54 radical 3 units squared.

Geometry. 
Anonymous,
In wikipedia type hexagon
Area:
A=t^2*[3*sqroot(3)]/2
54*sqroot(3)=t^2*[3*sqroot(3)]/2
Divide booth sides with sqroot(3)
54=3*t^2/2
54*2=3t^2
108=3t^2 Divide booth sides with 3
108/3=t^2
t^2=36
t=6
Perimeter:
P=6*t=6*6=36