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April 17, 2014

April 17, 2014

Posted by **Jessica** on Friday, April 8, 2011 at 6:22pm.

Values for dimension of the base are: ?

The height of the box is: ?

- CALC -
**bobpursley**, Friday, April 8, 2011 at 7:46pml=5w

costbase= lw*5

cost sides=3(2lh+2wh)

volume=lwh

25=lwh

or h= 25/wl

costtotal=5(lw*5)+3(2l*25/wl + 2w*25/wl)

costtotal=25lw+ 150/w+150/l

but l=5w

costtotal= 125w^2+150/w+30/w

take the derivative of cost.

costtotal'=0=250w-150/w^2-30/w^2

solve for w:

250w^3-180=0

w^3=180/250

w= cubroot 7.2

l= 4 cubroot 7.2

h= 25/(lw)

check my work.

- CALC -
**Anonymous**, Monday, January 2, 2012 at 2:55pmmoron

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