if a feeder gives food at 15o g every hour and it holds 3 kg of food for how many hours will it be activated?
the rate of delivery is 150 g h^-1
so the length of time is
3000 g/150 g h^-1
20 h
Note the unit conversion to g.
Note that the unit g cancels and we end up with just h, unit of time, which is what we want.
do you mean how many hours will it take for the feeder to give all of the food he/she is holding? if so,
then we first convert 3 kg to grams:
1 kg = 1000 g ; thus
3 kg = 3000 g
now we divide 3000 by 150 to get the time needed:
3000 / 150 = 20 hours
hope this helps~ :)
What does ml, cm, kg, and xm have in common?
To find out how many hours the feeder will be activated, we need to determine how many times it will dispense 150g of food until the entire 3kg (3000g) of food is used up.
First, let's determine how many times the feeder can dispense 150g of food from the 3kg supply:
3000g ÷ 150g = 20
Therefore, the feeder can dispense 150g of food 20 times before the supply is empty.
Since the feeder dispenses food every hour, it will be activated for 20 hours in total.