Posted by **lali** on Thursday, April 7, 2011 at 9:10pm.

wats xsquared-13x+36=0

- Math -
**Writeacher**, Thursday, April 7, 2011 at 9:14pm
Please type your __subject__ in the **School Subject** box. Any other words, __including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

- mmh -
**Anonymous**, Thursday, April 7, 2011 at 10:13pm
sqroot(0)=0

you must find where is:

-13x+36=0

-13x=-36 Divide with -13

x=(-36)/(-13)

x=36/13

- mmh - the correct answer and spelling of "math." -
**MattsRiceBowl**, Friday, April 8, 2011 at 12:33am
I have no idea what Anonymous did. That answer makes no sense.

x^2-13x+36 is the same as:

(x-4)(x-9)

Any number multiplied by 0 is 0. For example:

100 x 0 = 0

8 x 0 = 0

63655215777999400525 x 0 = 0

So if x-4 equals 0 OR x-9 equals zero, then we know that x-4 times x-9 equals zero.

x-4 = 0. In that case, x=4. (4-4 is zero)

x-9 = 0. So in that case, x=9. (9-9 = 0)

So x is either 4 or 9. Let's check to be sure.

4:

x squared is 16

13x is 52

36 is...well...36.

16 -52 + 36 does equal 0. So we are ok there.

9:

9 squared is 81

13 x 9 = 117

81 - 117 + 36 equals zero.

9 and 4 are your answers.

Side note: if writeteacher didn't correct your spelling of "math," I likely would not have seen this question. Be careful next time.

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