wats xsquared-13x+36=0
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sqroot(0)=0
you must find where is:
-13x+36=0
-13x=-36 Divide with -13
x=(-36)/(-13)
x=36/13
I have no idea what Anonymous did. That answer makes no sense.
x^2-13x+36 is the same as:
(x-4)(x-9)
Any number multiplied by 0 is 0. For example:
100 x 0 = 0
8 x 0 = 0
63655215777999400525 x 0 = 0
So if x-4 equals 0 OR x-9 equals zero, then we know that x-4 times x-9 equals zero.
x-4 = 0. In that case, x=4. (4-4 is zero)
x-9 = 0. So in that case, x=9. (9-9 = 0)
So x is either 4 or 9. Let's check to be sure.
4:
x squared is 16
13x is 52
36 is...well...36.
16 -52 + 36 does equal 0. So we are ok there.
9:
9 squared is 81
13 x 9 = 117
81 - 117 + 36 equals zero.
9 and 4 are your answers.
Side note: if writeteacher didn't correct your spelling of "math," I likely would not have seen this question. Be careful next time.
To solve the equation x^2 - 13x + 36 = 0, we can use the quadratic formula. The quadratic formula is used to find the solutions of any quadratic equation in the form ax^2 + bx + c = 0, with the variables a, b, and c representing the coefficients of the equation.
The quadratic formula states that the solutions of the equation ax^2 + bx + c = 0 are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our equation x^2 - 13x + 36 = 0, we have a = 1, b = -13, and c = 36. Plugging these values into the quadratic formula, we get:
x = (-(-13) ± √((-13)^2 - 4 * 1 * 36)) / (2 * 1)
Simplifying further:
x = (13 ± √(169 - 144)) / 2
x = (13 ± √25) / 2
Now, we have two possible solutions:
x₁ = (13 + 5) / 2 = 18 / 2 = 9
x₂ = (13 - 5) / 2 = 8 / 2 = 4
Therefore, the solutions to the equation x^2 - 13x + 36 = 0 are x = 9 and x = 4.