i never can do word problems....please help... i got 7 of them.....these are word for word

1)
Larry is 8 yrs older than his sister.In 3 yrs, hr will be twice as old as she will be then.how old is each now?

2)
Jennifer is 6 yrs older than Sue. in 4 yrs, she will be twice as old as Sue was 5 yrs ago. Find their ages now.

3)
Adam is 5 yrs younger than Eve. In 1 yr, Eve will be three times as old as Adam was 4 yrs ago. Find their ages now.

4)jack is twice as old as Jill. In 2 yrs, Jack will be 4 times as old as Jill was ( uears ago. How old are they now?

5)
four yrs ago, Katie was twice as old as Anne was then. In 6 yrs, Anne will be the same age that Katie is now How old is each now?

6)
five yrs ago, Tom was one third as old as his father was then. In 5 yrs Tom will be half as old as his father will be then. Find their ages now.

7)
Barry is 8 yrs older than sue. In 4 yrs, she will be twice as old as Sue was 5 yrs ago. find their ages now.

1. Larry's sister = X yrs old.

Larry = (X+8)yrs old.

In 3 yrs:
Larry = X+11.
Sister = X+3.

X+11 = 2(X+3),
X+11 = 2X+6,
X-2X = 6-11,
-X = -5,
X = 5yrs = sister's age.
X+8 = 5+8 = 13YRS = Larry's age.

2. Sue = X yrs old.
Jennifer = (x+6) yrs old.

X+10 = 2(X-5),
X+10 = 2X-10,
X-2X = -10-10,
-X = -20,
X = 20 yrs = Sue's age.
x+6 = 20+6 = 26 yrs = Jennifer's age.

3. Eve = X yrs old.
Adam = (X-5) yrs old.

X+1 = 3(X-5-4). Solve for X.

4. Jill = X yrs old.
Jack = 2x yrs old.

4(x-7) = 2x+2. Solve for x.

5. 4 yrs ago: Anne = x yrs old; Katie = 2x yrs old.

NOW: Anne=(x+4)yrs old; Katie = (2x+4)
yrs old.

x+10 = 2x+4.
x-2x = 4-10,
-x = -6,
x = 6.

x+4 = 6+4 = 10yrs = Anne's age.
2x+4 = 2*6 + 4 = 16 yrs = Katie's age.

6. 5yrs ago: Tom's father = x yrs old.
Tom = x/3 yrs old.

NOW: Tom's father = (x+5)yrs old.
Tom = (x/3+5)yrs old.

5yrs from now:
(x/3+10) = (x+10)/2 = (x/2)+5,
(x/3)+10 = (x/2)+5,
x/3-x/2 = 5-10 = -5,
Multiply both sides by 6:
2x-3x = -30,
-x = -30,
x = 30.

x+5=30+5 = 35 yrs = Tom's father's age.

x/3+5 = 30/3 + 5 = 15yrs = Tom's age.

7. NOW: Sue = x yrs old.
Barry = (x+8)yrs old.

4 yrs from now:
x+12 = 2(x-5). Solve for x and (x+8).

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To solve these word problems, you can follow a general approach:

1. Read the problem carefully and identify the given information. Note down any relationships, comparisons, or conditions mentioned in the problem.

2. Assign variables to unknown quantities. For example, if the problem asks for the ages of two people, you can use variables like "x" and "y" to represent their ages.

3. Translate the given information into equations or inequalities. Use the relationships mentioned in the problem to create an equation or inequality that represents the relationship between the variables.

4. Solve the equations or inequalities. Use algebraic techniques like simplifying, factoring, or isolating variables to find the values of the unknowns.

Now, let's apply this approach to solve each of the word problems you provided:

1) Larry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now?

Let's assume Larry's age is represented by "x" and his sister's age is represented by "y."

Given: x = y + 8 (Larry is 8 years older than his sister)
In 3 years: x + 3 = 2(y + 3) (Larry will be twice as old as his sister)

Now we have a system of two equations:
x = y + 8
x + 3 = 2(y + 3)

By solving this system of equations, we can find the values of x (Larry's age) and y (his sister's age).

2) Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now.

Let's assume Jennifer's age is "x" and Sue's age is "y."

Given: x = y + 6 (Jennifer is 6 years older than Sue)
In 4 years: x + 4 = 2(y - 5) (Jennifer will be twice as old as Sue was 5 years ago)

Now we have a system of two equations:
x = y + 6
x + 4 = 2(y - 5)

By solving this system of equations, we can find the ages of Jennifer and Sue.

You can use the same approach to solve the remaining word problems by assigning variables, setting up equations or inequalities, and then solving them using algebraic techniques.