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An 8.5 x 10^2 elevator is pulled up at a constant velocity of 1 m/s by a 10 kW motor. Calculate the efficiency of the motor.

  • Physics -

    power in work= mgh/t=8.5E2*9.8*1m/s=about 5000 watts

    Efficiencey appx= 5000/10K aboaut 50 percent.

    check that.

  • Physics -

    You have to provide dimensions along with the 850 for the elevator.

    M g V is the power delivered.

    Divide that by 10,000 W for the efficiency

  • Physics -

    Ok thanks to both for the answers!

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