Posted by Wendy A. on .
An 8.5 x 10^2 elevator is pulled up at a constant velocity of 1 m/s by a 10 kW motor. Calculate the efficiency of the motor.
power in work= mgh/t=8.5E2*9.8*1m/s=about 5000 watts
Efficiencey appx= 5000/10K aboaut 50 percent.
You have to provide dimensions along with the 850 for the elevator.
M g V is the power delivered.
Divide that by 10,000 W for the efficiency
Ok thanks to both for the answers!