Posted by **Anonymous** on Thursday, April 7, 2011 at 12:11am.

the widthe width of a rectangle is 6 inches less than the length. the perimeter is 72 inches. find the lengtj and the width

- geometry -
**Jai**, Thursday, April 7, 2011 at 10:18am
first represent unknowns using variables:

let x = length of rectangle

let x-6 = width of rectangle (according to first statement of problem)

now we set up equation,, since in the problem we are given the perimeter, we can use this to set up the equation,,

recall that perimeter of rectangle is

P = 2*(L+W)

where L is the length and W is the width

substituting,

72 = 2[ x + (x - 6) ]

we can divide both sides by 2 (to cancel 2 on the right side):

72/2 = x + x - 6

36 = 2x - 6

42 = 2x

x = 21 inches (length)

x-6 = 15 inches (width)

hope this helps~ :)

- geometry -
**rolo**, Saturday, April 20, 2013 at 11:20am
cool

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