Post a New Question


posted by .

The Hubble Space Telescope orbits the Earth at an approximate altitude of 612 km. Its mass is 11,100 kg and the mass of the Earth is 5.97×1024 kg. The Earth's average radius is 6.38×106 m. What is the magnitude of the gravitational force that the Earth exerts on the Hubble?

  • Physics -

    Your mass and radius of the Earth are not correct.
    The Earth's radius is 6380 km .

    F = Msat*Mearth*G/Rsat^2

    = Msat* g * (Rearth/R)^2

    Rsat = Rearth + 612 km = 6992 km
    Re/R = 0.9125

    g = 9.81 m/s^2

    Hubble's weight in that orbit is
    (0.9125)^2 = 83.3% of its weight on the Earth's surface.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question