What is the magnitude of the force per meter of length on a straight wire carrying an 8.50 -A current when perpendicular to a 0.55 -T uniform magnetic field?
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To find the magnitude of the force per meter of length on a straight wire carrying a current when perpendicular to a uniform magnetic field, you can use the formula:
F = BIL
where:
F is the force on the wire
B is the magnetic field strength
I is the current in the wire
L is the length of the wire
In this case, the current (I) is 8.50 A and the magnetic field (B) is 0.55 T. Since we want the force per meter of length, we can set the length (L) to be 1 meter.
Substituting these values into the formula, we get:
F = (0.55 T) * (8.50 A) * (1 meter)
F = 4.675 N
Therefore, the magnitude of the force per meter of length on the wire is 4.675 N.
To find the magnitude of the force per meter of length on a straight wire carrying a current when perpendicular to a uniform magnetic field, you can use the formula:
F = BIL
where:
F is the force on the wire (in newtons)
B is the magnetic field strength (in tesla)
I is the current flowing through the wire (in amperes)
L is the length of the wire (in meters)
In this case, the current flowing through the wire is 8.50 A and the magnetic field strength is 0.55 T. However, we need to consider the length of the wire per meter.
Now that we have the formula and the values, we can substitute them into the equation:
F = (0.55 T) * (8.50 A) * 1 m
Simplifying, we get:
F = 4.675 N/m
Therefore, the magnitude of the force per meter of length on the wire is 4.675 N/m.
F = B I L
F/L = B I
Just multiply the B and I numbers you have for magnetic field and current, and you will get the force in newtons per meter.