Write the overall ionic equation and the net ionic equation for the reaction between BaCl2 and Na2SO4 in aqueous solution, indentify the spectator ion and the precipitate ion for this reaction. help :(
Here is the net ionic equation. A bunch of typing for the others.
Ba^+2(aq) + SO4^-2(aq) ==> BaSO4(s)
To write the overall ionic equation and the net ionic equation for the reaction between BaCl2 and Na2SO4, we need to first determine the products formed when these two compounds combine.
1. BaCl2 dissociates into Ba2+ and 2Cl- ions in water.
BaCl2 -> Ba2+ + 2Cl-
2. Na2SO4 dissociates into 2Na+ and SO4 2- ions in water.
Na2SO4 -> 2Na+ + SO4 2-
Now, let's combine the ions to form the products:
Ba2+ + 2Cl- + 2Na+ + SO4 2- -> Ba2+ + 2Na+ + 2Cl- + SO4 2-
Considering the law of conservation of mass, we can eliminate the spectator ions, which are the ions that remain unchanged throughout the reaction. In this case, the spectator ions are Ba2+ and SO4 2-, as they are present on both sides of the equation.
After removing the spectator ions, the remaining equation is the net ionic equation:
2Na+ + 2Cl- -> 2NaCl
The precipitate ion in this reaction is Cl-, which combines with Na+ to form the precipitate NaCl.