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A 53 kg bungee jumper jumps from a bridge. She is tied to a bungee cord whose unstretched length is 13 m, and falls a total of 35 m. Calculate the spring stiffness constant k of the bungee cord, assuming Hooke's law applies.

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    Let X be the deflection from the zero-stretch length (13).

    When motion is considered, max spring potential energy (at max stretch) equals the gravitational potential energy loss at maximum extension.

    (1/2)k Xmax^2 = M g *35 m

    Xmax = 22 m

    k = 2 M g *35m/(22)^2
    = 75.1 Newton/meter

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