Posted by **ash** on Wednesday, April 6, 2011 at 12:51pm.

solve this linear programming problem;

A chain saw requires 4 hours of assembly and a wood chipper 6 hours. A maximum of 48 hours of assembly time is available. The profit is $150 on a chain saw and $220 on a chipper. How many of each should be assembled for maximum profit??

Thanks in advance guys!! =]

- linear programming app -
**MathMate**, Wednesday, April 6, 2011 at 1:25pm
Let C=chipper, S=chain saw

Objective function:

P(S,C)=150S + 220C

Constraints:

C≥0

S≥0

4S+6C≤48

There are three straight lines, so check the three intersections for the maximum values of the profit=P(S,C).

I see assembling chain-saws a little more profitable than chippers.

By the way, lady math tutors devote their time here too!

- linear programming app -
**Kay**, Friday, January 29, 2016 at 12:08pm
(12,8)

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