linear programming app
posted by ash on .
solve this linear programming problem;
A chain saw requires 4 hours of assembly and a wood chipper 6 hours. A maximum of 48 hours of assembly time is available. The profit is $150 on a chain saw and $220 on a chipper. How many of each should be assembled for maximum profit??
Thanks in advance guys!! =]
Let C=chipper, S=chain saw
P(S,C)=150S + 220C
There are three straight lines, so check the three intersections for the maximum values of the profit=P(S,C).
I see assembling chain-saws a little more profitable than chippers.
By the way, lady math tutors devote their time here too!