An investor had a total of 25,000 put into a portfolio of stocks, bonds, and mutual funds. In one year, he earned 8% on the stock investment, 10% on the bond investment and 6% on the mutual funds investment. The annual(simple interest) return was $1860. if the amount invested in the mutual fund was twice the investment in bonds, then how much did he originally put in each of the three individual investments?

an investor invested a total of 1800$ in two mutual funds. one fund earned a 5 % profit while the other earned a 3% profit. if the investor's total profit was 80$, how much was investad in mutual fund?

An investor earned $1,462.50 on an investment of $90,000 in 65 days. Find the annual simple interest rate earned on the investment.

To solve this problem, we need to set up equations based on the given information and then solve them simultaneously.

Let's assume the amount invested in stocks is S, the amount invested in bonds is B, and the amount invested in mutual funds is M.

From the problem statement, we know that:
1) The total amount invested was $25,000, so we have the equation: S + B + M = 25,000.

2) The investor earned an 8% return on the stock investment, a 10% return on the bond investment, and a 6% return on the mutual funds investment. From this information, we can calculate the return received for each investment:
- Return on stocks = 8% of S = 0.08S
- Return on bonds = 10% of B = 0.1B
- Return on mutual funds = 6% of M = 0.06M

3) The annual return on the investments was $1860, so we have the equation: 0.08S + 0.1B + 0.06M = 1860.

4) The amount invested in mutual funds was twice the investment in bonds, so we have the equation: M = 2B.

Now we will solve the equations simultaneously to find the values of S, B, and M.

Substituting M = 2B into the first equation:
S + B + 2B = 25,000
S + 3B = 25,000

Rearranging the equation:
S = 25,000 - 3B

Substituting M = 2B into the third equation:
0.08S + 0.1B + 0.06(2B) = 1860
0.08S + 0.1B + 0.12B = 1860
0.08S + 0.22B = 1860

Substituting S = 25,000 - 3B into the above equation:
0.08(25,000 - 3B) + 0.22B = 1860
2000 - 0.24B + 0.22B = 1860
-0.02B = -140
B = 7000

Substituting B = 7000 into the equation M = 2B:
M = 2(7000)
M = 14,000

Substituting B = 7000 into the equation S = 25,000 - 3B:
S = 25,000 - 3(7000)
S = 25,000 - 21,000
S = 4000

Therefore, the investor originally put $4000 into stocks, $7000 into bonds, and $14,000 into mutual funds.