Posted by **Anonymous** on Wednesday, April 6, 2011 at 2:00am.

A rumor spreads through a population in such a way that "t" hours after the rumor starts, the percent of people involved in passing it on is given by P(t)=100[e^(-t)-e^(-4t)]. What is the highest percent of people involved in spreading the rumor within the first 3 h? When does this occur?

## Answer this Question

## Related Questions

- Calculus - The number, N, of people who have heard a rumor spread by mass media ...
- calculus - N(t) = 650 1+649 e−0.5 t . (You may wish to sketch a graph of ...
- Calculus I, differentiation - The number, N, of people who have heard a rumor ...
- Calculus - N(t) = 650/1+649 e^−0.5 t (b) How many people will have heard ...
- calculus - The rate at which a rumor spreads through an Alpine village of 400 ...
- Math - The number, N, of people who have heard a rumor spread by mass media by ...
- Calculus - The number of people that hear a rumor follows logistic growth. In a ...
- Math - I can't calculate 1 as the answer given to the following problem. I keep ...
- Precal - The number of people in a town of 10,000 who have heard a rumor started...
- math - number of people who hear a rumor after t hours is N(t) = 2000/ 1 + 499e...

More Related Questions