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April 18, 2015

April 18, 2015

Posted by **Cady** on Tuesday, April 5, 2011 at 11:29pm.

f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals.

Enter -1000 for any absolute extrema that does not exist.

(A) Interval = [1,4]

Absolute maximum =

Absolute minimum =

(B) Interval = [1,8] .

Absolute maximum =

Absolute minimum =

(C) Interval = [4,9] .

Absolute maximum =

Absolute minimum =

My answers are:

(A) Interval = [1,4]

Absolute maximum = 9

Absolute minimum = -5

(B) Interval = [1,8] .

Absolute maximum = 173

Absolute minimum = -5

(C) Interval = [4,9] .

Absolute maximum = 459

Absolute minimum = -1000

Only the max for the second one and the max for the third one are right.... I don't know what to do....

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