Homework Help: Calculus (pleas help!!!)

Posted by Cady on Tuesday, April 5, 2011 at 11:29pm.

Find the absolute maximum and absolute minimum values of the function

f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals.
Enter -1000 for any absolute extrema that does not exist.

(A) Interval = [1,4]
Absolute maximum =

Absolute minimum =

(B) Interval = [1,8] .
Absolute maximum =

Absolute minimum =

(C) Interval = [4,9] .
Absolute maximum =

Absolute minimum =

My answers are:
(A) Interval = [1,4]
Absolute maximum = 9

Absolute minimum = -5

(B) Interval = [1,8] .
Absolute maximum = 173

Absolute minimum = -5

(C) Interval = [4,9] .
Absolute maximum = 459

Absolute minimum = -1000

Only the max for the second one and the max for the third one are right.... I don't know what to do....

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