Thursday

July 24, 2014

July 24, 2014

Posted by **Cady** on Tuesday, April 5, 2011 at 11:07pm.

f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals.

Enter -1000 for any absolute extrema that does not exist.

(A) Interval = [1,4]

Absolute maximum =

Absolute minimum =

(B) Interval = [1,8] .

Absolute maximum =

Absolute minimum =

(C) Interval = [4,9] .

Absolute maximum =

Absolute minimum =

My answers are:

(A) Interval = [1,4]

Absolute maximum = 9

Absolute minimum = -5

(B) Interval = [1,8] .

Absolute maximum = 173

Absolute minimum = -5

(C) Interval = [4,9] .

Absolute maximum = 459

Absolute minimum = -1000

Only the max for the second one and the max for the third one are right.... I don't know what to do....

- Calculus (pleas help!!!) -
**Mgraph**, Wednesday, April 6, 2011 at 11:05amf'(x)=(x-5)^3+(x-2)3(x-5)^2=(4x-11)(x-5)^2

(A) Absmax=f(1)=64+11=75

Absmin=f(11/4)=-3^7/2^8+11=-2187/256+

+11=629/256

(B) Absmax=f(8)=173

Absmin=f(11/4)=629/256

(C) Absmax=f(9)=459

Absmin=f(4)=9

**Related Questions**

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...

Calculus - Find the absolute maximum and absolute minimum values of the function...

math calculus - Find the absolute extrema of the function on the closed interval...

Applied Calculus - Find the absolute maximum and absolute minimum values, if any...

Math I'm so confused - Find the absolute maximum and absolute minimum values, if...

Calculus Help Please!!! - Find the absolute maximum and absolute minimum values ...

calculus - Find the absolute maximum and absolute minimum values of f on the ...

Calculus Help Please!!! - Find the absolute maximum and absolute minimum values ...

Calculus Help Please!!! - Find the absolute maximum and absolute minimum values ...

Calculus Help Please!!! - Find the absolute maximum and absolute minimum values ...