Na2CO3
write the hydrolysis reaction for the salts. Dissociate the salt into cation and anion and ignore inert species
This salt is formed from the Na+ ion and the carbonate ion. However, because Na+ reacts with water to form a strong base (NaOH) there is no reaction for that species because it dissociates completely. When the carbonate ion reacts with water, its negative 2 charge causes its protonation as it accepts the proton from water forming bicarbonate and hydroxide ions. Therefore the hydrolysis reaction for the salt ignoring the inert species is
CO3(2-) + H2O ⇌ HCO3(-) + OH(-)
This is a basic salt because it produces hydroxide ions. When dissolved in water this salt would cause an increase in the pH.
To determine the hydrolysis reaction of Na2CO3, we first need to break down the salt into its cation and anion. In this case, Na2CO3 dissociates into two sodium ions (Na+) and one carbonate ion (CO3^2-).
Now, let's consider the hydrolysis of these ions.
1. Sodium ion (Na+):
Sodium ions are derived from a strong base (NaOH). Since sodium ions come from the strong base, they do not undergo hydrolysis. Hence, they will remain unchanged in the presence of water.
2. Carbonate ion (CO3^2-):
The carbonate ion can react with water (H2O) to form hydroxide ions (OH-) and carbonic acid (H2CO3).
CO3^2- + H2O → OH- + HCO3^-
In this reaction, the carbonate ion acts as a base, accepting a proton (H+) from water to form hydroxide ions, and forming bicarbonate (or hydrogen carbonate) ions.
So, in summary, the hydrolysis reaction of Na2CO3 can be represented as follows:
Na2CO3 + H2O → 2Na+ + OH- + HCO3-