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The sum of the squares of three consecutive positive integers is 365
What are these integers?
Please write this problem in quadratic equation form please

  • Maths - ,

    let x = smallest integer, then the other integers are x+1 and x +2.

    x^2 + (x+1)^2 + (x+2)^2 = 365

    Square terms and combine.

  • Maths - ,

    X^2+(x+1^2)+(x+2^2)=365 3x^2+6x-360=0 x^2+2x-120=0 (x+12)(x-10)=0 x=10 or -12 Answer=10,11,12 or -12,-11,-10

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