Posted by Jane911 on Tuesday, April 5, 2011 at 5:43pm.
The sum of the squares of three consecutive positive integers is 365
What are these integers?
Please write this problem in quadratic equation form please

Maths  PsyDAG, Tuesday, April 5, 2011 at 8:29pm
let x = smallest integer, then the other integers are x+1 and x +2.
x^2 + (x+1)^2 + (x+2)^2 = 365
Square terms and combine.

Maths  Vin mwale, Thursday, December 3, 2015 at 6:01am
X^2+(x+1^2)+(x+2^2)=365 3x^2+6x360=0 x^2+2x120=0 (x+12)(x10)=0 x=10 or 12 Answer=10,11,12 or 12,11,10
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