Posted by **Jane911** on Tuesday, April 5, 2011 at 5:43pm.

The sum of the squares of three consecutive positive integers is 365

What are these integers?

Please write this problem in quadratic equation form please

- Maths -
**PsyDAG**, Tuesday, April 5, 2011 at 8:29pm
let x = smallest integer, then the other integers are x+1 and x +2.

x^2 + (x+1)^2 + (x+2)^2 = 365

Square terms and combine.

- Maths -
**Vin mwale**, Thursday, December 3, 2015 at 6:01am
X^2+(x+1^2)+(x+2^2)=365 3x^2+6x-360=0 x^2+2x-120=0 (x+12)(x-10)=0 x=10 or -12 Answer=10,11,12 or -12,-11,-10

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