posted by Eliz on .
I am stuck on this question and not really sure what to do for it. I think that i can use this equation Q/dt=e*sigma*A*T^4 for it, but i'm not getting the right answer for it. Is this not the right equation?
Electronics and inhabitants of the International Space Station generate a significant amount of thermal energy that the station must get rid of. The only way that the station can exhaust thermal energy is by radiation, which it does using thin, 1.8 -by-3.6 panels that have a working temperature of about 6. How much power is radiated from each panel? Assume that the panels are in the shade so that the absorbed radiation will be negligible.
Hint: Don't forget that the panels have two sides!
I assume you are using radiating temperature as 6K.
Now, on absorbed radiation. Do you mean from the Sun (in the shade)? But in the shade, the background radiation is about 2.3K. I guess I am not certain what you are doing.