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October 25, 2014

October 25, 2014

Posted by **Lu** on Tuesday, April 5, 2011 at 1:03pm.

y= -5x^1/2 + X^3/2; X=25

- business calculus -
**Reiny**, Tuesday, April 5, 2011 at 1:55pmdy/dx = (-5/2)x^(-1/2) + (3/2)x^(1/2)

= -5/(2√x) + 3√x/2

when x = 25

y = -5(√25) + (√25)^3 = -25 + 125 = 100

dy/dx = -5/(2√25) + 3√25/2 = -1/2 + 15/2 = 7

then

(y-100) = 7(x-25)

Finish it up to express the final equation is the form you want.

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