business calculus
posted by Lu on .
find the slope of the tangent line
y= 5x^1/2 + X^3/2; X=25

dy/dx = (5/2)x^(1/2) + (3/2)x^(1/2)
= 5/(2√x) + 3√x/2
when x = 25
y = 5(√25) + (√25)^3 = 25 + 125 = 100
dy/dx = 5/(2√25) + 3√25/2 = 1/2 + 15/2 = 7
then
(y100) = 7(x25)
Finish it up to express the final equation is the form you want.