If a 25.0 mL sample of 0.500 M HCl solution were diluted 125-fold, what would be the volume and concentration of the diluted solution?

Would the total volume be 25*125 = 3125 mL?

And the concn would be
0.500 x (25.0/3125) = ??

.004

To find the volume and concentration of the diluted solution, you can use the dilution formula equation, which states that the initial concentration multiplied by the initial volume is equal to the final concentration multiplied by the final volume.

Here are the steps to calculate the volume and concentration of the diluted solution:

1. Calculate the initial number of moles of HCl in the 25.0 mL sample.
- Moles of solute = Concentration × Volume
- Moles of HCl = (0.500 M) × (25.0 mL * 10^-3 L/mL)

2. Use the dilution formula equation to find the final volume:
- Initial concentration × Initial volume = Final concentration × Final volume
- (0.500 M) × (25.0 mL * 10^-3 L/mL) = Final concentration × Final volume

3. Rearrange the equation and solve for the final volume:
- Final volume = (Initial concentration × Initial volume) / Final concentration
- Final volume = [(0.500 M) × (25.0 mL * 10^-3 L/mL)] / (125)

4. Calculate the final volume in mL:
- Final volume (mL) = Final volume (L) × (1000 mL/1 L)

5. Calculate the final concentration of the diluted solution:
- Final concentration = Initial concentration / Dilution factor
- Dilution factor = Final volume / Initial volume

Now, let's calculate the volume and concentration of the diluted solution.

Step 1:
Moles of HCl = (0.500 M) × (25.0 mL * 10^-3 L/mL)
Moles of HCl = 0.0125 moles

Step 2:
(0.500 M) × (25.0 mL * 10^-3 L/mL) = Final concentration × Final volume

Step 3:
Final volume = [(0.500 M) × (25.0 mL * 10^-3 L/mL)] / (125)
Final volume = 0.100 mL

Step 4:
Final volume (mL) = 0.100 L × (1000 mL/1 L)
Final volume = 100 mL

Step 5:
Dilution factor = Final volume / Initial volume
Dilution factor = 100 mL / 25 mL
Dilution factor = 4

Final concentration = Initial concentration / Dilution factor
Final concentration = 0.500 M / 4
Final concentration = 0.125 M

Therefore, the volume of the diluted solution is 100 mL, and the concentration of the diluted solution is 0.125 M.

To determine the volume and concentration of the diluted solution, we can use the dilution formula:

C1V1 = C2V2

where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution

Given:
C1 = 0.500 M
V1 = 25.0 mL
C2 = unknown
V2 = unknown

Let's substitute the values into the dilution formula and solve for C2:

(0.500 M)(25.0 mL) = C2(V2)

We are given that the initial volume (V1) is 25.0 mL and the solution is diluted 125-fold. This means the final volume (V2) will be 125 times larger than the initial volume.

V2 = (125)(V1)
V2 = (125)(25.0 mL)
V2 = 3125 mL

Now, let's substitute this value of V2 back into the dilution formula:

(0.500 M)(25.0 mL) = C2(3125 mL)

Solving for C2:

C2 = (0.500 M)(25.0 mL) / (3125 mL)
C2 = 0.004 M

Therefore, the volume of the diluted solution is 3125 mL and the concentration of the diluted solution is 0.004 M.