Posted by Anonymous on Monday, April 4, 2011 at 3:14pm.
a. When half over, you have some HC2H3O2 not yet titrated, you have some extra water produced, some NaC2H3O2 (the sodium acetate salt) produced (present as Na^+ and C2H3O2^-).
b. When half over, the pH = pKa
c. The pH at the equivalence point is determined by the salt present; i.e., one has only water and the salt at that point. The pH of NaC2H3O2 (the salt of a strong base and a weak acid) is basic so the pH is >7 (about 8.5 or so).
Related Questions
chemistry - How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O ...
Chemistry - How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O ...
chemistry desperately - i am completely lost, i confused myself. i need to find ...
chemistry - titration - Show that for the titration of a weak acid, HA, with ...
chemistry - which of the following was not one of the products when you titrated...
chemistry - What is the mole ratio between all compounds of this reaction:...
Chemistry 1115 - What is the chemical equation for the reaction that occurs ...
Chemistry - At 25°C, K = 0.090 for the following reaction:H2O(g) + Cl2O(g) 2...
chemistry - We are determining the molarity of HCl by titration of HCl. What ...
chemistry - HCl is titrated with NaOH. When doing the titration, some of the ...
For Further Reading