posted by B on .
Consider 125 mL of 0.110 M MgCl2 solution.
a. How many moles of MgCl2 are contained in 125 mL of 0.0110 M MgCl2?
b. What is the concentration of Mg2+ ion?
c. What is the concentration of Cl- ion?
moles MgCl2 = M x L = ??
b. Since there is 1 atom Mg per molecule of MgCl2, the concn Mg = concn MgCl2.
c. Since there are two atoms Cl per molecule of MgCl2, the concn of Cl ions is twice that of MgCl2 or Mg.