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March 31, 2015

March 31, 2015

Posted by **jjj** on Monday, April 4, 2011 at 1:00pm.

- algebra -
**Damon**, Monday, April 4, 2011 at 1:26pmt going upstream

(5 - t) going downstream

speed upstream = (v-3)

speed downstream = (v+3)

36 = t(v-3)

36 = (5-t)(v+3)

36 = t v - 3 t

t = 36/(v-3)

36 = [5 - 36/(v-3)] (v+3)

36 = 5(v+3) - 36(v+3)/(v-3)

(21 - 5 v)(v-3) = -36(v+3)

check, multiply out and solve quadratic for v

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