Posted by **Aestas** on Monday, April 4, 2011 at 11:08am.

Two 75.0-kg hockey players skating at 5.25 m/s collide and stick together. If the angle between their initial directions was 140 degrees, what is their speed after the collision? (Let the motion of player 1 be in the positive x-direction and the motion of player 2 be at an angle of 140 degrees measured counterclockwise from the positive x-axis.

So I've got the mass(1) and mass(2) = 75 kg. and velocity (1) and velocity (2) = 5.25 m/s. They stick together, so it's inelastic collision.

I used the equation m(1)v(1) + m(2)v(2) = (m(1)+m(2))v(final).

The then solved for the x and y components of v(final) at the angle of 70 degrees. But came up with the wrong answers for each one.

What did I do wrong? I honestly don't know what I did wrong. Please help me!

## Answer This Question

## Related Questions

- physics - Two 72.0 kg hockey players skating at 5.25 m/s collide and stick ...
- physics - Two 72.0-kg hockey players skating at 7.00 m/s collide and stick ...
- physics - Two 72.0 kg hockey players skating at 7.00 m/s collide and stick ...
- College Physics - Two 72.0-kg hockey players skating at 7.00 m/s collide and ...
- skylin - Two 75.0-kg hockey players skating at 5.75 m/s collide and stick ...
- physics - Two 75.0 kg hockey players skating at 5.60 m/s collide and stick ...
- PHYSICS - Two 75 kg hockey players skating at 5.50 m per s collide and stick ...
- Physics 101 - Two ice skaters, each with a mass of 72.0 kg, are skating at 5.10 ...
- Physics - Two hockey pucks approach each other as shown in the figure below. ...
- Physics - momentum - Two hockey pucks approach each other as shown in the figure...

More Related Questions