Posted by Anonymous on Monday, April 4, 2011 at 9:50am.
"Using Lagrange multipliers, find the maximum value of f(x,y) = x + 3y + 5z subject to the constraint x^2 + y^2 + z^2 = 1."
Any help would be appreciated!
- Calculus - MathMate, Monday, April 4, 2011 at 4:55pm
This can be solved by geometry.
The constraint is the surface of a sphere of radius 1.
The given plane has a normal unit vector of (i+3j+5k)/sqrt(1²+3²+5²)
So the maximum and minimum value of x+3y+5z is at
Which when substituted into the equation of the plane gives P(x,y,z)=1.
Using Lagrange multipliers:
where L=lagrange multiplier (lambda)
Partially differentiate with respect to x, y and z gives the first order conditions:
∂P/∂x = 1+2xL = 0
∂P/∂y = 3+2yL = 0
∂P/∂z = 5+2zL = 0
Solve for x,y and z in terms of L and substitute in the constraint equation of x²+y²+z²=1
(-1/2L)²+(3/2L)²+(5/2L)² = 1
Solve for L to get
Substitute to get maximum
x= 1/2L = 1/sqrt(35)
y= 3/2L = 3/sqrt(35)
z= 5/2L = 5/sqrt(35)
Answer This Question
More Related Questions
- Calculus - "Using Lagrange multipliers, find the minimum value of f(x,y) = x^2...
- cal - Using a Lagrange Multiplier with One Constraint. Find the maximum value of...
- calculus - Use Lagrange multipliers to find the max/min values of the function f...
- cal3 please help! - Use Lagrange multipliers to find the max/min values of the ...
- calculus - Use Lagrange multipliers to find the maximum and minimum values of f(...
- :( please help answer cal problem - Use lagrange multipliers to find the max and...
- Math - Use lagrange multipliers to find the point on the plane x-2y 3z-14=0 that...
- calculus - to find the possible relative extrema of the function f(x,y) subject ...
- Optimization - min 2x+y subject to: x+y+z=1 and y^2+z^2=4 Any help would greatly...
- Calculus - Q. Find the minimum value of Q=x^2y subject to the constraint 2x^2+...