Posted by **Anonymous** on Monday, April 4, 2011 at 1:24am.

how to find equation of horizontal tangent line of 2y^3+6x^2y-12x^2+6y=1

## Answer this Question

## Related Questions

- Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...
- please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Need help fast on calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy...
- Math - Use linear approximation, i.e. the tangent line, to approximate 1.6^3 as ...
- Calculus - Let f(x)=3x^4-2x^2+3 a) find f'(x) Answer: f'(x)=12x^3-4x b) find the...
- cal - find the equation of a quadratic function whose graph is tangent at x=1 to...
- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- College Math - I have been struggling with this problem I cannot get the right ...
- calculus - If the tangent line to the function f(x)=x+a at x=16 has equation y=...

More Related Questions