Monday

July 28, 2014

July 28, 2014

Posted by **deek** on Monday, April 4, 2011 at 12:24am.

- math -
**Jai**, Monday, April 4, 2011 at 4:13amwhen an object is dropped from a certain height, it is a freefall. when in freefall, the only external force acting on the body is gravitational force (neglecting air resistance). the motion of the object is unformly accelerated motion:

(v2)^2 - (v1)^2 = 2*g*h

where

v2 = final velocity

v1 = initial velocity

h = height or distance traveled

g = acceleration due to gravity (9.8 m/s^2)

solving for velocity:

v2 = sqrt[ 2gh - (v1)^2 ]

when the object starts from rest (and thus v1 = 0),

v2 = sqrt(2gh)

hope this helps~ :)

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