Posted by Cassie on .
What is the percent ionization for each of the following acids?
a. 0.022 M HClO2 solution of pH= 3.88
Answer obtained: .60%
pH = 10^(-3.88) = 1.32 x 10^-4
% ionization= [H+] formed divided by
MHA (original acid concent) x 100
= (1.32x10^-4)/0.022 x 100
b. 0.0027 M HClO2 solution of pH=4.70
Answer obtained from solving: .44%
pH = 10^(-4.70) = 1.20 x 10^-5
= (1.20x1-^-5)/0.0027 x 100
I can't check your answers because you didn't provide the Ka for HClO2. I don't have it listed in any of my references.