posted by Adrianna on .
The compound A1B2 (molar mass = 132) has a solubility of 13 g/L. Calculate the Ksp for this compound.
I'm stuck on this question, please help?
AB2 ==> A^+2 + 2B^-
solubility AB2 in moles/L = 13 g/L/molar mass AB2 = ??
(AB2) = ??
(A^+2) = ?? (same as AB2)
(B^-) = 2 x ??
Ksp = (A^+2)(B^-)^2 = you work it out.