Homework Help: Physics

Posted by Jeannine on Sunday, April 3, 2011 at 8:35pm.

a shaft rotation @ 800 rpm delivers a torque of 240 N.m to an output shaft that is rotating @ 200 rpm.
a. if the efficiency of the machine is 70%, compute the output torque
b, what is the output power

e=Po/Pi .7=x/240 N.m = 168 N.m

this is not the answer in the book so I obviously have no idea what I am doing...help?

Physics - bobpursley, Sunday, April 3, 2011 at 9:35pm
.7=Torque*200/240*600

torque out=.7*3*240

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