User: in 1995, the life expectancy of males in a certian country was 67.3 years. In 2001, it was 69.8 years. let E represent the life expectency in year t and let t represent the number of years since 1995.
e9t)-_t+_
e(11)=_
To find the life expectancy in the year 2011, we need to use the given data and the equation provided.
Let's break down the information we have:
- In 1995, the life expectancy of males was 67.3 years.
- In 2001, the life expectancy of males was 69.8 years.
Now, let's use the equation provided:
E(t) = e^(9t) - t + e^(11)
First, let's determine the value of t for the year 2011. Since we're looking for the number of years since 1995, we can calculate it as:
t = 2011 - 1995
t = 16
Now, let's substitute this value of t into the equation:
E(16) = e^(9*16) - 16 + e^(11)
To simplify further, let's calculate the exponential terms:
e^(9*16) ≈ 3.26901737 × 10^10
e^(11) ≈ 5.98741417 × 10^4
Now, let's substitute these values into the equation:
E(16) = 3.26901737 × 10^10 - 16 + 5.98741417 × 10^4
We can simplify and calculate this expression to find the life expectancy in 2011.