Posted by Mango on Sunday, April 3, 2011 at 5:19pm.
Coulombs = A x sec = 1.70 x 2 x 60 x 60 = ??
One equivalent weight will be deposited by passing 96,495 coulombs. ONe equivalent weight = 63.54 g/2 = 31.8 but you need to do that more accurately.
Then
31.8 x #coulombs/96,485 = g Cu deposited.
g Cu initially = 2L x 0.580M x 63.54 = ??
g Cu deposted from above = xx
g Cu remaining in solution = zz
M = moles/2L = zz
This assumes no electrolysis of the water (highly unlikely I think).
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