Posted by Jake on Sunday, April 3, 2011 at 2:35pm.
(1/2) k x^2 + (1/2)mV^2 = 0.21 J
= total energy = constant
Set V = 0 to solve for the amplitude, since V = 0 then
When displacement is half the amplitude, potential energy is 1/4 of the total, 0.1575 J
When KE = PE,
(1/2) kx^2 = 0.015 J. Solve for x at that time
The phase angle depends upon what you call zero phase. Yopu haven't said
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