Posted by **-** on Sunday, April 3, 2011 at 9:47am.

the velocity of the water jet discharging from the orifice can be obtained from v = (2gh)^(1/2), where h = 2m is the depth of the orifice from the free water surface. determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits the surface.

- physics -
**drwls**, Sunday, April 3, 2011 at 10:03am
That will depend upon how far below the orifice that point B is. A figure should tell you that. We cannot see your figure.

- physics -
**sam**, Sunday, November 20, 2016 at 9:03am
Vx = sqrt(2gh)

y=y0 + Vy *t - 1/2gt^2

-1.5= -1/2gt^2

solve for t

t= 0.553

x=x0 + vx*t ,x0 = 0

x=3.4641m

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