net ionic equation of aluminum hydroxide + sodium hydroxide
what makes you think there is a reaction at all?
To find the net ionic equation for the reaction between aluminum hydroxide (Al(OH)3) and sodium hydroxide (NaOH), we need to first write the balanced chemical equation.
The balanced chemical equation for the reaction between aluminum hydroxide and sodium hydroxide is:
Al(OH)3 + 3NaOH → Al(OH)3 + 3NaOH
Next, we need to identify the ions that are present in the solution and determine which ones participate in the chemical reaction.
Aluminum hydroxide dissociates in water to form aluminum ions (Al3+) and hydroxide ions (OH-):
Al(OH)3(s) → Al3+(aq) + 3OH-(aq)
Similarly, sodium hydroxide dissociates to form sodium ions (Na+) and hydroxide ions (OH-):
NaOH(s) → Na+(aq) + OH-(aq)
Now, we can write the ionic equation by combining the ions that participate in the reaction, leaving out any spectator ions:
Al3+(aq) + 3OH-(aq) + 3Na+(aq) + 3OH-(aq) → Al(OH)3(s) + 3Na+(aq) + 3OH-(aq)
Simplifying the equation by canceling out the common ions present on both sides of the equation:
Al3+(aq) + 3OH-(aq) + 3Na+(aq) + 3OH-(aq) → Al(OH)3(s) + 3Na+(aq) + 3OH-(aq)
The net ionic equation for the reaction between aluminum hydroxide and sodium hydroxide is:
Al3+(aq) → Al(OH)3(s)
This represents the molecular species that undergoes a chemical change in the reaction.