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February 26, 2015

February 26, 2015

Posted by **michele** on Saturday, April 2, 2011 at 10:13am.

a.(i) {(a, 0), (c, 1), (d, -1)}

b.(ii) {(a, -1), (b, -1), (c, 0), (d, 1)}

c.(iii) {(a, 1), (b, 1), (c, 0), (d, O)}

d.(iv) ({a, 1), (b, 0), (c, -1), (o.O), (a, -1)}

answer choice are

a.(i) and (iv)

b.(i) and (iii)

c.(ii) and Oii)

d.(iii) and (iv)

V

- math -
**bobpursley**, Saturday, April 2, 2011 at 11:24ami is a one to one mapping, but all do not map. Where does b map to?

ii is a one to one, each abcd maps to a unique map

iii each a,b,c, d maps to a particular choice.

iv how can (a) map to 1 and -1 and be a function? It cant.

so ii, iii are functions. check my logic.

So,

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