Posted by Veronica on .
Okay, today, I find myself utterly dumbfounded by these three questions 
Write a proof for 
2/(sqrt(3)cos(x) + sin(x))= sec((pi/6)x)
Solve the following equation 
2sin(2x)  2sin(x) + 2(sqrt(3)cos(x))  sqrt(3) = 0
Find all solutions (exact) to the equation 
sin^2(x)cos^2(x) = (2  sqrt(2))/16
Any Help at all will most definitely be appreciated!!!

URGENT  Trigonometry  Identities and Proofs 
Reiny,
In proving identities the general rule is to start with the more complicated side and, by mathematical manipulation, show that it is equal to the other side.
(even though it may not look it, in your problem the rights side (RS) is more complicated, so ....
RS = 1/cos(π/6x)
= 1/cos(30°x) , it makes no difference if you work in degrees or radians
= 1/(coss30cosx + sin30sinx)
= 1/((√3/2)cosx + (1/2)sinx)
= 1/((√3cosx + sinx)/2)
= 2/(√3cosx + sinx)
= LS
Do either solve or prove these type of equations, you have to be familiar with the basic trig relationships, such as
cos(A±B) = cosAcosB /+ sinAsinB, which I used above.
I also needed to know the trig ratios of the standard 306090 rightangled triangle.
in the first of your "solve equation" we will need
sin(2A) = 2sinAcosA
2sin(2x)  2sinx + 2√3cosx  √3 = 0
4sinxcosx  2sinx +2√3cosx  √3 = 0
common factors
2sinx(2cosx  1) + √3(2cosx  1) = 0
(2cosx  1)(2sinx + √3) = 0
2cosx1 = 0 or 2sinx + √3 = 0
cosx = 1/2 or sinx = √3/2
the last of these is not possible since the sine and the cosine fall between 1 and +1
so cosx = 1/2
from the 306090 triangle , we know cos 60° = 1/2
and by the CAST rule, the cosine is positive in I and IV
so x = 60° or x = 300°
or
x = π/3 or x = 5π/3 radians.
last one:
sin^2x cos^2x = (2√2)/16
take √ of both sides
sinxcosx = ±√(2√2)/4
4sinxcosx = ±√(2√2
2sin 2x = ±√(2√2)
sin2x = ±√(2√2)/2
so 2x is in any of the 4 quadrants
using my calculator , I evaluated the right side, then by "inverse sin", found
2x = 22.5° ( ahh, 1/2 of the 45, one of the standard angles)
so 2x = 22.5 or 157.5 or 202.5 or 337.5
making
x = 11.25 , 78.75 , 101.25 or 168.75
since the period of sin2x , which gave us our answer, is 180/2 or 90°, adding or subtracting multiples of 90 to any of the above answers will produce a new answer.
e.g. 78.75+90= 168.75° will also be an answer.
let's test that:
sin^2 (168.75) + cos^2(168.75)
= .036611651 by calculator
RS = (2√2)/16 = .036611652 , not bad eh? 
Appendex  URGENT  Trigonometry  Identities and Proofs 
Reiny,
In the second equation I rejected
sinx = √3/2
I shouln't have since that value lies between 1 and 1
from the above we also get
x = 120° or x =240°
or
x = 2π/3 or x = 4π/3 rads