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November 21, 2014

November 21, 2014

Posted by **Anonymous** on Friday, April 1, 2011 at 1:04am.

- geometry -
**drwls**, Friday, April 1, 2011 at 7:17amLet the shortest leg length be a.

Area = (a)*(3a/2)*(1/2) = (3/4)a^2 = 12

a^2 = 16

a = 4 and the other leg (which we'll call b) must be 6.

Use the Pythagorean theorem for the hypotenuse, c.

c^2 = a^2 + b^2

c = sqrt(52) = 7.2111 inch

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