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calculus

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Please can someone help. I need to use the composite rule to differentiate the function f(x)=(x^2-6x+23)^3/2. Any help would be greatly appreciated.

  • calculus - ,

    I don't know what name they give the rule these days, but the way I do it would get you ...

    f'(x) = (3/2)(2x-6)(x^2 - 6x + 23)^(1/2) in one step.
    and
    = 3(x-3)√(x^2 - 6x + 23)

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