the ratio of the corresponding sides of two similar triangles is 7:5 what is the ratio of their perimeters

Since both the length of sides and perimeter are linear

the perimeters would be in that same ratio of 7 : 5

To find the ratio of the perimeters of two similar triangles, we'll use the fact that the ratio of corresponding sides is equal to the ratio of the perimeters.

Let's assume that the ratio of their corresponding sides is 7:5.

If the ratio of the corresponding sides is 7:5, then the ratio of their perimeters is also 7:5.

So, the ratio of their perimeters is 7:5.

To find the ratio of the perimeters of two similar triangles, you need to consider that the ratio of their corresponding sides is 7:5.

Let's say the ratio of their perimeters is "x:y". The perimeter of a triangle is the sum of the lengths of its three sides. So, if the sides of the first triangle are 7x, 7y, and 7z, and the sides of the second triangle are 5x, 5y, and 5z, we can write:

Perimeter of the first triangle = 7x + 7y + 7z
Perimeter of the second triangle = 5x + 5y + 5z

Now, we need to determine the relationship between these perimeters.

Since the sides of the second triangle are smaller by a factor of 7/5 compared to the first triangle, we can say that the ratio of their perimeters will also be 7/5.

Therefore, the ratio of their perimeters is 7:5.

49:35