Posted by **Rhonda** on Thursday, March 31, 2011 at 11:32am.

if (a+b)squared=64, and ab=3, find a squared+ b squared

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**Jai**, Thursday, March 31, 2011 at 11:55am
we can also rewrite this (a+b)squared=64 as

(a+b)^2 = 64

first we expand (a+b)^2

(a+b)^2 = 64

(a+b)(a+b) = 64

a^2 + 2ab + b^2 = 64

since we are given the value of ab, which is ab = 3, we can substitute it here:

a^2 + 2(3) + b^2 = 64

a^2 + 6 + b^2 = 64

a^2 + b^2 = 64 - 6

a^2 + b^2 = 58

hope this helps~ :)

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