Posted by **Lizabeth** on Thursday, March 31, 2011 at 1:49am.

How much heat is required to raise 75 grams of 0 degree Celsius ice to 135 degree Celsius steam?

- Chemistry -
**Jai**, Thursday, March 31, 2011 at 3:10am
to get the heat released or absorbed,

Q = mc(T2-T1)

where

m = mass of substance (units in g)

c = specific heat capacity (units in J/g-K)

T2 = final temperature

T1 = initial temperature

**note: if Q is (-), heat is released and if (+), heat is absorbed

now we can only apply this to substances that did not change its phase, but in the problem, we see that phase change occurs. from ice->water->steam

thus we need another data called it Latent Heat of Fusion and Latent Heat of Vaporization to calculate for the heat required to change its phase:

H1 = m(Lf)

H2 = m(Lv)

where

m = mass

Lf = Latent Heat of Fusion (fusion means melting)

Lv = Latent Heat of Vaporization (vaporization means from liquid, it becomes vapor)

the heat required to raise the LIQUID's temp (from 0 C to 100 C) is

Q1 = mc(100 - 0) = 100*75*c = 7500*c

the heat required to raise the STEAM's temp (from 100 to 135) is

Q2 = mc(135 - 100) = 35*75*c

thus the total heat needed is:

Q,total = H1 + Q1 + H2 + Q2

note that can find c, Lf and Lv of water in books or you can just google it. remember and be careful of the units.

hope this helps~ :)

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