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March 1, 2015

March 1, 2015

Posted by **Chuck** on Wednesday, March 30, 2011 at 8:09pm.

HELP

- Math -
**drwls**, Wednesday, March 30, 2011 at 11:55pm1 - 3 - 7 - 6 - 9

2 - 4 - 7 - 8 - 5

7 is at the intersection and gets used twice.

Since the sum of all digits is 45, and you want more than half of that for the total on both rows, the shared digit in the middle had to be slightly above the mean (5).

I tried 6 and then 7. The rest was easy.

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