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September 17, 2014

Homework Help: trig

Posted by Sushmitha on Wednesday, March 30, 2011 at 6:12pm.

use an inverse trig function to write as a function of x

(There is a right triangle.
The hypotenuse is 2.
is the angle between the base and the hypotenuse.
The base/adjacent side of is (x + 1)
The side opposite does not have a value.)

a) = sqrt [4 - (x + 1)^2] all divided by 2

b) = cos ^ -1 [(x + 1)/2]

c) = tan ^ -1 [(x + 1)/2]

d) = sin ^ -1 [2/(x + 1)]

How do I do this? I'm leaning towards B, the inverse cosine because only the adjacent side and hypotenuse are given. The opposite side is not given, and there is already a variable x in the given adjacent side.

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