Posted by **Anonymous** on Wednesday, March 30, 2011 at 11:26am.

Find the absolute maximum value and the absolute minimum value, if any, of the function.

g(x) = -x(^2) + 2 x + 9

- math -
**drwls**, Wednesday, March 30, 2011 at 11:43am
g'(x) = -2x + 2

This is zero when x = 1.

The second derivative, -2, is negative there, so g(1) is a maximum. The value there is 10.

There is no absolute minimum. The function is an upside-down parabola that goes to minus infinity at large and small x.

- math -
**Bosnian**, Wednesday, March 30, 2011 at 10:03pm
In google type:

functions graphs online

When you see list of results click on:

rechneronline.de/function-graphs/

When page be open in blue recatacangle type:

-x^2 + 2 x + 9

In Display properties set:

Range y-axis from -7 to 13

Then click option Draw

You will see graph of your function.

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